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Change lzo/xtea eternexus

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Hi, how i can edit keys in eternexus? 1b582228d32803cc783d0335c6352598.png

 

"official" keys 

static DWORD s_adwEterPackKey[] =
{
    45129401,
    92367215,
    681285731,
    1710201,
};

static DWORD s_adwEterPackSecurityKey[] =
{
    78952482,
    527348324,
    1632942,
    486274726,
};

I must convert keys to eternexus or what? 

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13 minutes ago, Sirio said:

https://mega.nz/#!t5ElwCrC!4GWAk4bLU1DXm1u3nPGkL8qUuUrQrRjPmSDIPa2MgCM

b99eb0026f69810563989b2879181a00 its example key but my keys is not too long like this key. WTF? XD I change keys in eterpack.cpp now i must change keys in eternexus. How can i do this? 

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You must find the 16 exadecimals of xtea and lzo (this are the default key, you must find yours)

like this (i use HxD)

Immagine.png

and then put it in the python file i gave you before

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On 5/6/2018 at 11:20 AM, ReFresh said:

@.Rise Try to learn some python basics.

And could you help me please?
As I can see, you know it very well :)

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On 8/15/2016 at 1:07 PM, Sirio said:

https://mega.nz/#!t5ElwCrC!4GWAk4bLU1DXm1u3nPGkL8qUuUrQrRjPmSDIPa2MgCM

Hello, thank you, but I have problem.. It happens, when I input: "b99eb0026f69810563989b2879181a00"


Traceback of python script:

Spoiler

Traceback (most recent call last):
  File "keyconverter.py", line 5, in <module>
    lista=struct.unpack("LLLL", string.decode('hex'))
struct.error: unpack requires a string argument of length 32
 

 

Code:

#!/usr/local/bin/python2.7
import struct
print "Example of a key (Standard): b99eb0026f69810563989b2879181a00\n"
string=raw_input("Insert the hexadecimal key: ")
lista=struct.unpack("LLLL", string.decode('hex'))
n=0
print "\nGenerator: \n"
for i in lista:
    n+=1
    i=str(i)
    i=i.replace("L", "")
    print "A" + str(n) + " = " + i

Could you help me, please?

Thank you!

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